Mr.

Series and duplicate corporation Purpose/Problem: To gain the remnants between serial and analog connections. Materials: Circuit Board solution Battery Holder 2 Light Bulbs With Holders Switch Wires Washers secure Connectors Procedures: 1)Connect the set out electric-light bulbs in a serial connection. 2)Answer the questions pertaining to series connections. 3)Connect the groundless bulbs in a mate connection. 4)Answer the questions pertaining to match connections. password Questions: 1 Light Bulb = 5Ω Series Connection 1)Connecting only 1 diminish bulb in the travel would make the virtuoso bulb glow brighter. 2)If one of the legerity bulbs becomes unscrewed /discommitted, the rest of the light bulbs wont work. 3)6V / 10Ω nub = 0.6A, Yes, the amperes is the aforementioned(prenominal) throughout, because this is a series circuit, which I is constant. 4)Yes, the electromotive force difference crossways each light bulb is the kindred, because each one has interchangeable current. Parallel Connection 1)The amount of light bulbs connected in agree has no effect on the brightness of the individualistic bulbs.

2)If one of the light bulbs becomes unscrewed / disconnected in the 2 light bulb parallel circuit, the other remaining light bulb will fluent continue to function, which would not be the exemplar if this circuit was connected in series. 3)The 2 bulbs in parallel are brighter versus 2 bulbs in series, because the light bulbs in parallel share the same potential difference, which series connections do not. 4)1/5Ω + 1/5Ω = 0.2Ω + 0.2Ω = 0.4&#! 8486; = 1/0.4Ω = 2.5Ω Total. 6V / 2.5Ω = 2.4A. No the current isnt the same throughout, because the total current = sum of all currents. 5)Yes, the potential difference between each light bulb is the same. Conclusions: The major object in this lab was to understand the differences between series and parallel connections. Also, we had to use Ohms Law to calculate the...If you involve to live on a full essay, order it on our website: BestEssayCheap.com

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